How to check Even or Odd number in Java Program ?

  Java Interview Q&A

In this program, you will learn to check whether the number entered by the user is even or odd. This will be done using the … if statement and the ternary operator in Java.

Example 1: Check Even or Odd number in Java Program

import java.util.Scanner;

class CheckEvenOdd
{
  public static void main(String args[])
  {
    int num;
    System.out.println("Enter an Integer number:");

    //The input provided by user is stored in num
    Scanner input = new Scanner(System.in);
    num = input.nextInt();

    /* If number is divisible by 2 then it's an even number
     * else odd number*/
    if ( num % 2 == 0 )
        System.out.println("Entered number is even");
     else
        System.out.println("Entered number is odd");
  }
}

Output 1:

Enter an Integer number:
78
Entered number is even

Output 2:

Enter an Integer number:
77
Entered number is odd

Example 2: Check whether a number is even or odd using if…else statement

import java.util.Scanner;

public class EvenOdd {

    public static void main(String[] args) {

        Scanner reader = new Scanner(System.in);

        System.out.print("Enter a number: ");
        int num = reader.nextInt();

        if(num % 2 == 0)
            System.out.println(num + " is even");
        else
            System.out.println(num + " is odd");
    }
}

Output

Enter a number: 12
12 is even

Example 3: Check whether a number is even or odd using ternary operator

import java.util.Scanner;

public class EvenOdd {

    public static void main(String[] args) {

        Scanner reader = new Scanner(System.in);

        System.out.print("Enter a number: ");
        int num = reader.nextInt();

        String evenOdd = (num % 2 == 0) ? "even" : "odd";

        System.out.println(num + " is " + evenOdd);

    }
}

Output

Enter a number: 13
13 is odd

 

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